Increment of Success - Revision history

Castus: /* Swift Edition Rules */

2021-12-29T01:52:49Z

Swift Edition Rules

Castus: /* Swift Edition Rules */

2021-12-29T01:52:21Z

Swift Edition Rules

Castus: /* Swift Edition Rules */

2021-12-29T01:51:27Z

Swift Edition Rules

Castus: /* Swift Edition Rules */

2021-12-29T01:49:17Z

Swift Edition Rules

Castus: /* Swift Edition Rules */

2021-12-29T01:22:36Z

Swift Edition Rules

Castus at 01:21, 29 December 2021

2021-12-29T01:21:16Z

Castus: Created page with "'''Increment of success''' details how successful an action is. This is most often used to calculate damage, but it can be used for any action. ==Dealing Damage== A simple e..."

2020-12-07T05:10:47Z

Created page with "'''Increment of success''' details how successful an action is. This is most often used to calculate damage, but it can be used for any action. ==Dealing Damage== A simple e..."

New page

'''Increment of success''' details how successful an action is. This is most often used to calculate damage, but it can be used for any action.

==Dealing Damage==
A simple example: if a player needs to get 3 dice rolls under a 7 to be successful, rolling exactly 3 right is equal to 1 increment of success. The IoS goes up from there for every 1 die that's successful. So rolling 5 good dice would then be an IoS of 3 (1 for the match of 3, and 1 for each subsequent successful die thereafter). Thus, the damage dealt by the weapon would be multiplied by 3.

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 Because you use 2d10s in [[Swift Edition Rules|swift edition]], determining IoS isn't as straightforward, but it's still simple. Because there are a possible 20 rolls (2d10), simply divide the distance from the target roll by two (round down for odds). Examples:
-*if you need to roll 14 and you roll a [[File:d10-7.png|30px]][[File:d10-bk5.png|30px]] the difference is 2 (12 is 2 away from 14). Divide by 2, giving you a difference of 1. Add the default of 1 (success), makes this a total IoS of 2.
+*if you need to roll 14 and you roll a [[File:d10-7.png|36px]][[File:d10-bk5.png|36px]] the difference is 2 (12 is 2 away from 14). Divide by 2, giving you a difference of 1. Add the default of 1 (success), makes this a total IoS of 2.
-*if you need to roll 11 and you roll a [[File:d10-4.png|30px]][[File:d10-bk2.png|40px]] the difference is 5. Divide that by 2 (rounding down), gives a difference of 2, plus the default of 1 (success). Total IoS = 3.
+*if you need to roll 11 and you roll a [[File:d10-4.png|36px]][[File:d10-bk2.png|36px]] the difference is 5. Divide that by 2 (rounding down), gives a difference of 2, plus the default of 1 (success). Total IoS = 3.
 *How many dice away from the target roll is your roll? Divide that by 2 (round down for odd), then add 1 to that number and you have the IoS.

@@ Line 14: / Line 14: @@
 *if you need to roll 14 and you roll a [[File:d10-7.png|30px]][[File:d10-bk5.png|30px]] the difference is 2 (12 is 2 away from 14). Divide by 2, giving you a difference of 1. Add the default of 1 (success), makes this a total IoS of 2.
-*if you need to roll 11 and you roll a [[File:d10-4.png|30px]][[File:d10-bk2.png|20px]] the difference is 5. Divide that by 2 (rounding down), gives a difference of 2, plus the default of 1 (success). Total IoS = 3.
+*if you need to roll 11 and you roll a [[File:d10-4.png|30px]][[File:d10-bk2.png|40px]] the difference is 5. Divide that by 2 (rounding down), gives a difference of 2, plus the default of 1 (success). Total IoS = 3.
 *How many dice away from the target roll is your roll? Divide that by 2 (round down for odd), then add 1 to that number and you have the IoS.

@@ Line 13: / Line 13: @@
 Because you use 2d10s in [[Swift Edition Rules|swift edition]], determining IoS isn't as straightforward, but it's still simple. Because there are a possible 20 rolls (2d10), simply divide the distance from the target roll by two (round down for odds). Examples:
-*if you need to roll 14 and you roll a [[File:d10-7.png|30px]][[File:d10-bk5.png|30px]], 12 is 2 away from 14. Divide by 2, giving you a difference of 1. Add the default of 1 (success), makes this a total IoS of 2.
+*if you need to roll 14 and you roll a [[File:d10-7.png|30px]][[File:d10-bk5.png|30px]] the difference is 2 (12 is 2 away from 14). Divide by 2, giving you a difference of 1. Add the default of 1 (success), makes this a total IoS of 2.
-*if you need to roll 11 and you roll 6, the difference is 5. Divide that by 2 (rounding down), gives a difference of 2, plus the default of 1 (success). Total IoS = 3.
+*if you need to roll 11 and you roll a [[File:d10-4.png|30px]][[File:d10-bk2.png|20px]] the difference is 5. Divide that by 2 (rounding down), gives a difference of 2, plus the default of 1 (success). Total IoS = 3.
 *How many dice away from the target roll is your roll? Divide that by 2 (round down for odd), then add 1 to that number and you have the IoS.

@@ Line 13: / Line 13: @@
 Because you use 2d10s in [[Swift Edition Rules|swift edition]], determining IoS isn't as straightforward, but it's still simple. Because there are a possible 20 rolls (2d10), simply divide the distance from the target roll by two (round down for odds). Examples:
-*if you need to roll 14 and you roll a 12, 12 is 2 away from 14. Divide by 2, giving you a difference of 1. Add the default of 1 (success), makes this a total IoS of 2.
+*if you need to roll 14 and you roll a [[File:d10-7.png|30px]][[File:d10-bk5.png|30px]], 12 is 2 away from 14. Divide by 2, giving you a difference of 1. Add the default of 1 (success), makes this a total IoS of 2.
 *if you need to roll 11 and you roll 6, the difference is 5. Divide that by 2 (rounding down), gives a difference of 2, plus the default of 1 (success). Total IoS = 3.

@@ Line 13: / Line 13: @@
 Because you use 2d10s in [[Swift Edition Rules|swift edition]], determining IoS isn't as straightforward, but it's still simple. Because there are a possible 20 rolls (2d10), simply divide the distance from the target roll by two (round down for odds). Examples:
-*if you need to roll 14 and you roll a 12, 12 is 2 away from 14. Divide by 2, giving you a total IoS of 2 (success is always a default of 1, plus the die roll result).
+*if you need to roll 14 and you roll a 12, 12 is 2 away from 14. Divide by 2, giving you a difference of 1. Add the default of 1 (success), makes this a total IoS of 2.
-*if you need to roll 11 and you roll 6, the difference is 5. Divide that by 2 (rounding down), gives a difference of 2, plus the default of 1. Total IoS = 3.
+*if you need to roll 11 and you roll 6, the difference is 5. Divide that by 2 (rounding down), gives a difference of 2, plus the default of 1 (success). Total IoS = 3.
 *How many dice away from the target roll is your roll? Divide that by 2 (round down for odd), then add 1 to that number and you have the IoS.

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-'''Increment of success''' details how successful an action is. This is most often used to calculate damage, but it can be used for any action.
+'''Increment of success''' details ''how successful an action is''. This is most often used to calculate damage, but it can be used for any action. The idea behind it is to allow for a greater range of options when it comes to pass/failure types of things. For example, in a binary system, or pass/fail system, there are only two options: either you succeed or you fail. By including degrees of success, or ''increments'', you can now enjoy greater latitude. One might barely graze an opponent with their blade, for example, or they may hack an opponent completely in half. Both are successful hits, but to varying degrees of success.
 ==Dealing Damage==
 A simple example: if a player needs to get 3 dice rolls under a 7 to be successful, rolling exactly 3 right is equal to 1 increment of success. The IoS goes up from there for every 1 die that's successful. So rolling 5 good dice would then be an IoS of 3 (1 for the match of 3, and 1 for each subsequent successful die thereafter). Thus, the damage dealt by the weapon would be multiplied by 3.